p^2-10p-46=0

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Solution for p^2-10p-46=0 equation:


Simplifying
p2 + -10p + -46 = 0

Reorder the terms:
-46 + -10p + p2 = 0

Solving
-46 + -10p + p2 = 0

Solving for variable 'p'.

Begin completing the square.

Move the constant term to the right:

Add '46' to each side of the equation.
-46 + -10p + 46 + p2 = 0 + 46

Reorder the terms:
-46 + 46 + -10p + p2 = 0 + 46

Combine like terms: -46 + 46 = 0
0 + -10p + p2 = 0 + 46
-10p + p2 = 0 + 46

Combine like terms: 0 + 46 = 46
-10p + p2 = 46

The p term is -10p.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10p + 25 + p2 = 46 + 25

Reorder the terms:
25 + -10p + p2 = 46 + 25

Combine like terms: 46 + 25 = 71
25 + -10p + p2 = 71

Factor a perfect square on the left side:
(p + -5)(p + -5) = 71

Calculate the square root of the right side: 8.426149773

Break this problem into two subproblems by setting 
(p + -5) equal to 8.426149773 and -8.426149773.

Subproblem 1

p + -5 = 8.426149773 Simplifying p + -5 = 8.426149773 Reorder the terms: -5 + p = 8.426149773 Solving -5 + p = 8.426149773 Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + p = 8.426149773 + 5 Combine like terms: -5 + 5 = 0 0 + p = 8.426149773 + 5 p = 8.426149773 + 5 Combine like terms: 8.426149773 + 5 = 13.426149773 p = 13.426149773 Simplifying p = 13.426149773

Subproblem 2

p + -5 = -8.426149773 Simplifying p + -5 = -8.426149773 Reorder the terms: -5 + p = -8.426149773 Solving -5 + p = -8.426149773 Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + p = -8.426149773 + 5 Combine like terms: -5 + 5 = 0 0 + p = -8.426149773 + 5 p = -8.426149773 + 5 Combine like terms: -8.426149773 + 5 = -3.426149773 p = -3.426149773 Simplifying p = -3.426149773

Solution

The solution to the problem is based on the solutions from the subproblems. p = {13.426149773, -3.426149773}

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